Question

What should be added to $\frac{-13}{4}$ +$\frac{-3}{8}$ to get 1 ?

Answer 1

Lets assume we need to add x
$\frac{-13}{4}+\frac{(-3)}{8}+x=1$
$\Rightarrow \frac{-26-3}{8}+x=1$
$\Rightarrow x=1+\frac{29}{8}=\frac{29+8}{8}=\frac{29+8}{8}=\frac{37}{8}$
$\therefore \frac{37}{8}$ should be added to get 1