What should be added to the quadratic polynomial x²-5x+4 so that 3 is a zero of the resulting polynomial ?
P(x) = x2 - 5x + 4
P(3) = 32 - 5*3 + 4
P(3) = 9- 15 + 4
P(3) = -2
Since, -2 is the remainder,
Therefore, 2 must be added to P(x) So that 3 will be a zero of the polynomial.
Verification:
P(x) = x2 - 5x + 4
Adding 2,
P(x) = x2- 5x + 6
P(3) = 32 - 5*3 + 6
P(3) = 9 - 15 + 6
P(3) = 15-15
P(3) = 0
Hence, 2 is supposed to be added to the polynomial, for 3 to become a zero of the polynomial.