Question

What should be added to $x^2+3x-8$ to get $x^2+x+6$?

• A. $3x^2-8$
• B. $x+6$
• C. $2x+14$
• D. $-2x+14$

Answer 1

The correct option is D $-2x+14$

Here we have to subtract
($x^2$ + 3$x$ - 8) from ($x^2$ + $x$ + 6),
So, we have to find the solution of
($x^2$ + $x$ + 6) - ($x^2$ + 3$x$ - 8).

$(x^2+x+6)$
$-(x^2+3x-8)$
$\underset{–}{(-)(-)(+)}$
$0x^2-2x+14$

So, $(-2x+14)$ should be added to $(x^2+3x-8)$ to get $(x^2+x+6)$.