Question

What should be subtracted from $\frac{-3}{4}$ to get $\frac{5}{6}$?

Answer 1

$\begin{array}{l}\text{Let the required}\text{number that is to be subtracted}\mathrm{be}\text{x}.\\ \frac{-3}{4}-x=\frac{5}{6}\\ =>-x=\frac{5}{6}-\frac{(-3)}{4}\\ \mathrm{L}.\mathrm{C}.\mathrm{M}.\mathrm{of}6\mathrm{and}4\mathrm{is}12.\\ \begin{array}{l}=>-x=\frac{10+9}{12}\\ =>-x=\frac{19}{12}\\ =>-x\times \left(\text{-1}\right)=\frac{19}{12}\times \left(-1\right)\end{array}\\ \\ =>x=-\frac{19}{12}\\ \text{Hence, the required number is}\frac{-19}{12}\text{.}\end{array}$