Question

What should be subtracted from $\frac{-3}{4}$ to get $\frac{5}{6}$?
(a) $\frac{19}{12}$
(b) $\frac{-19}{12}$
(c) $\frac{1}{12}$
(d) $\frac{-1}{12}$

Answer 1

$$\begin{gathered} \begin{array}{l}\\ \mathrm{The}\mathrm{c}\text{orrect option is}\left(\text{b}\right).\\ \text{Let the number that is to be subtracted be}x.\\ \\ \frac{-3}{4}-x=\frac{5}{6}\\ =>-x=\frac{5}{6}-\left(\frac{-3}{4}\right)\\ =>-x=\frac{5}{6}+\frac{3}{4}\\ =>-x=\frac{(5\times 2)+(3\times 3)}{12}\\ =>x=-\frac{19}{12}\end{array} \\ \mathrm{Hence},-\frac{19}{12}\text{should be subtracted from}\frac{-3}{4}\text{to get}\frac{5}{6}\text{.} \end{gathered}$$