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Question

a) What should be subtracted from 3x24y2+5xy+20 to obtain x2y2+6xy+20?
b) Find the final expression when the algebraic expression x2+2xy+y2 is multiplied by xy. [4 MARKS]

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Solution

Each option: 1.5 Marks

a) Let q be the expression to be subtracted.

Then according to the question,

3x24y2+5xy+20q=x2y2+6xy+20

q=3x24y2+5xy+20(x2y2+6xy+20)

q=3x24y2+5xy+20+x2+y26xy20

q=3x2+x24y2+y2+5xy6xy+2020

q=4x23y2xy+0

Hence, 4x23y2xy should be subtracted from 3x24y2+5xy+20 to obtain x2y2+6xy+20.

b) As per the question:
x2+2xy+y2 is multiplied by xy

So, xy× x2+2xy+y2

=xy×x2+xy×2xy+xy×y2

=x2+1y+2x1+1y1+1+xy1+2

am×an=am+n

=x3y+2x2y2+xy3

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