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Question

Question 5

What should be subtracted from 3x24y2+5xy+20 to obtain x2y2+6xy+20?

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Solution

Let q be the expression to be subtracted.

Then according to the question,

3x24y2+5xy+20q=x2y2+6xy+20

q=3x24y2+5xy+20(x2y2+6xy+20)

q=3x24y2+5xy+20+x2+y26xy20

q=3x2+x24y2+y2+5xy6xy+2020

q=4x23y2xy+0

Hence, 4x23y2xy should be subtracted from 3x24y2+5xy+20 to obtain x2y2+6xy+20.


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