Question

What should be subtracted from $\frac{1}{18}$ to get $\frac{7}{12}$?

Answer 1

Let $x$ be subtracted from $\frac{1}{18}$ to get $\frac{7}{12}$.
So, $\frac{1}{18}-x=\frac{7}{12}$
$\Rightarrow x=\frac{1}{18}-\frac{7}{12}$
$\Rightarrow x=\frac{2-(7\times 3)}{36}$ [Since, LCM of $18$ and $12$ is $36$]
$\Rightarrow x=\frac{2-21}{36}$
$\therefore x=\frac{-19}{36}$.