What should be subtracted from $p^{2} - 6 p + 7$ so that the remainder may exactly be divisible by $(p - 1)$ ?

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Solution

The correct option is A 2
Put the value $p = 1$ in the given equation
$p^{2} - 6 p + 7$
$p (1) \Rightarrow (1)^{2} - 6 (1) + 7$
$p (1) \Rightarrow 1 - 6 + 7 = 2$
So, $2$ should be subtracted from the given equation to make it divisible by $(p - 1)$ .

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