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Question

What should be subtracted from x2xy+y2x+y+3 to obtain x2+3y24xy+1?

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Solution

Let ‘E’ be the required expression. Then, we have

x2xy+y2x+y+3E=x2+3y24xy+1

Therefore,E=(x2xy+y2x+y+3)(x2+3y24xy+1)

=x2xy+y2x+y+3+x23y2+4xy1

Collecting positive and negative like terms together, we get

x2+x2xy+4xy+y23y2x+y+31

=2x2+3xy2y2x+y+2

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