What should be taken away from $3 x^{2} - 4 y^{2} + 5 x y + 20 g e t - x^{2} - y^{2} + 6 x y + 20$ .

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Solution

Given $\Rightarrow$ $3 x^{2} - 4 y^{2} + 5 x y + 20$
Required $\Rightarrow$ $- x^{2} - y^{2} + 6 x y + 20$

Let the necessary cutoff expression be $a$ .

Then,
$\begin{matrix} 3 x^{2} - 4 y^{2} + 5 x y + 20 - a & = - x^{2} - y^{2} + 6 x y + 20 a & = 3 x^{2} - 4 y^{2} + 5 x y + 20 + x^{2} + y^{2} - 6 x y - 20 = x^{2} (3 + 1) + y^{2} (- 4 + 1) + x y (5 - 6) + 20 - 20 = 4 x^{2} - 3 y^{2} - x y \end{matrix}$

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Similar questions

3 x^{2} - 4 y^{2} + 5 x y + 20

- x^{2} - y^{2} + 6 x y + 20

3 x^{2} - 4 y^{2} + 5 x y + 20

- x^{2} - y^{2} + 6 x y + 20

3 x^{2} - 4 y^{2} + 5 x y + 20

- x^{2} - y^{2} + 6 x y + 20

Question 5

What should be subtracted from $3 x^{2} - 4 y^{2} + 5 x y + 20$ to obtain $- x^{2} - y^{2} + 6 x y + 20$ ?

3 x^{2} - 4 y^{2} + 5 x y + 20

- x^{2} - y^{2} + 6 x y + 20

x^{2} + 2 x y + y^{2}

x y

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