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Question

What should be taken away from 3x2 − 4y2 + 5xy + 20 to obtain

x2y2 + 6xy + 20?

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Solution

Let p be the required term.

(3x2 − 4y2 + 5xy + 20) − p = − x2y2 + 6xy + 20

p = (3x2 − 4y2 + 5xy + 20) − (− x2y2 + 6xy + 20)

= 3x2 − 4y2 + 5xy + 20 + x2 + y2 − 6xy − 20

= 3x2 + x2 − 4y2 + y2 + 5xy − 6xy + 20 − 20

= 4x2 − 3y2xy
​​​​​​​​​​​​​


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