What should be the acceleration ′a′ of the box shown in figure so that the block of mass m exerts a force mg4 on the floor of the box ? (where g is acceleration due to gravity)
A
3g4
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B
g4
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C
2g4
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D
4g4
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Solution
The correct option is A3g4 As lift is moving down
Net Normal reaction = N=m(g−a)
Given N=mg4 /mg4=/m(g−a) a=3g4(downwards)