Question

What should be the angle of incidence for a ray of light which suffers a minimum deviation of ${36}^o$ through an equilateral prism?

• A. ${12}^o$
• B. ${16}^o$
• C. ${24}^o$
• D. ${48}^o$

Answer 1

The correct option is D ${48}^o$

$A={60}^o,$
$i=\frac{A+{\delta }_{min}}{2}$
$=\frac{60+36}{2}$
$={48}^o$