What should be the angular velocity of rotation of the earth about its own axis so that the weight of a body at the equator reduces to 3/5 or its present value? (Take R as the radius of the earth)
A
√g3R
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B
√2g3R
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C
√2g5R
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D
√2g7R
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Solution
The correct option is D√2g5R mg′=mg−mRω2cos2ϕ Now, 35mg=mg−mRω2 or mRω2=mg−35mg or mRω2=25mg or ω=√2g5R