What should be the equivalent weight of phosphorous acid, if P=31; O=16; H=1

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20.5

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Solution

The correct option is B 41
The acid is dibasic.
Molecular weight of $H_{3} P O_{3} = 3 + 31 + 48 = 82$
$∴$ Equivalent weight $= \frac{M o l e c u l a r w e i g h t}{B a s i c i t y} = \frac{82}{2} = 41$ .

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