What should be the ratio of area of cross section of the master cylinder and wheel cylinder of a hydraulic brake so that a force of $15 N$ can be obtained at each of its brake shoe by exerting a force of $0.5 N$ on the pedal?

1 : 60

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1 : 30

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1 : 15

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1 : 45

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Solution

The correct option is D $1 : 30$
We know that $P_{1} = P_{2}$
$\Rightarrow \frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}$
$\Rightarrow \frac{A_{1}}{A_{2}} = \frac{F_{1}}{F_{2}} = \frac{1}{30}$
$\Rightarrow 1 : 30$

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What should be the ratio of area of cross section of the master cylinder and wheel cylinder of a hydraulic brake so that a force of 15N can be obtained at each of its brake shoe by exerting a force of 0.5N on the pedal?

The correct option is D 1:30We know that P1=P2⇒F1A1=F2A2⇒A1A2=F1F2=130⇒1:30

What should be the ratio of area of cross section of the master cylinder and wheel cylinder of a hydraulic brake so that a force of $15 N$ can be obtained at each of its brake shoe by exerting a force of $0.5 N$ on the pedal?

The correct option is D $1 : 30$
We know that $P_{1} = P_{2}$
$\Rightarrow \frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}$
$\Rightarrow \frac{A_{1}}{A_{2}} = \frac{F_{1}}{F_{2}} = \frac{1}{30}$
$\Rightarrow 1 : 30$