Question

What should be the reagent(s) and/or solvent to accomplish the following reaction?

• A. $NaB{H}_4$ in $C{D}_{3}OH$
• B. $NaB{D}_4$ in $C{D}_{3}OH$
• C. $NaB{D}_4$ in $C{H}_{3}OH$
• D. $NaB{D}_4$ in $C{D}_{3}OD$

Answer 1

The correct option is D

$NaB{D}_4$ in $C{D}_{3}OD$

$NaB{D}_4$, more specifically $[B{D}_4{]}^{-}$ is a $D^{-}$ donor and $D^{+}$ is given by the solvent.
so the solvent could be $D_{2}O$ or $C{H}_{3}OD$: