Question

What should be the size of the missing piece if the full rectangle corresponds to 1 unit?

\begin{tabular}{|l|l|l|} \hline \( 3 / 4 \) & \( ? \) & \( 1 / 6 \) \\ \hline \end{tabular}

• A. $\frac{1}{12}$
• B. $\frac{1}{16}$
• C. $\frac{3}{12}$
• D. $\frac{3}{16}$

Answer 1

The correct option is A

$\frac{1}{12}$

We first add $\frac{3}{4}+\frac{1}{6}.$

To add them, we need to find the LCM of 4 and 6.

LCM of 4 and 6 = 12

$\therefore \frac{3}{4}+\frac{1}{6}=\frac{3\times 3}{4\times 3}+\frac{1\times 2}{6\times 2}=\frac{9+2}{12}=\frac{11}{12}$

To find the missing piece, we subtract this sum from 1.

i.e., $1-\frac{11}{12}=\frac{12-11}{12}=\frac{1}{12}$