What should be the temperature rise of a brass rod , so as to increase its length by 1%? (Given: coefficient of linear expansion of glass rod, α=2×10−5∘C−1).
A
1000 0C
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B
500 0C
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C
200 0C
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D
100 0C
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Solution
The correct option is B
500 0C
Let, coefficient of linear expansion =α=2×10−5∘C−1 Initial length =l0 Final length =l Change in temperature =t Since, the length has to be increased by 1%, we have change in length =l−l0=0.01l0 We know, α×l0×t=l−l0 or, α×l0×t=0.01l0 ⇒2×10−5×t=0.01 ⇒t=0.012×105=500∘C