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Question

What should be the value of b, if the value of
(29x2+7x10+6b) is 18, when x=2?

A
15
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B
17
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C
19
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D
21
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Solution

The correct option is B 17
Given 29x2+7x10+6b=18

Substituting the value of x in the above expression, we get,

29(2)2+7(2)10+6b=18
116+1410+6b=18
120+6b=18
b=17

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