Question

What should be the value of $b$, if the value of $a^2-10a+b$ equals to $1$, for $a=1$?

Answer 1

Given:$a^2-10a+b=1$

For $a=1\Rightarrow 1-10\times 1+b=1$

$\Rightarrow 1-10+b=1$

$\therefore -10+b=0$

$\therefore b=10$