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Question

What should be the value of coefficient of static friction between the tyre and the road, when a car travelling at speed of 60 kmh1 makes a level turn of radius 40 m?

A
0.5
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B
0.66
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C
0.71
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D
0.80
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Solution

The correct option is C 0.71
Applying equation for frictional force as centripetal force at the circular turn gives,
f=mv2r
Here, f is magnitude of frictional force.
μmg=mv2r
μ=v2rg=(60×518)240×9.8=0.71

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