Question

What smallest digit be written in the blank space of the mumber ......6724 so that the number formed is divisible by 3?
(a) 3
(b) 4
(c) 2
(d) 1

Answer 1

A number is divisible by 3 if the sum of its digits is divisible by 3.
The sum of digits in 6724 is 6 + 7+ 2 + 4 = 19
For divisble by 3 we have to add 2 in 19 i.e., 2 + 19 = 21, which is divisible by 3.
Hence, the correct answer is option (c).