What strength does a fishing line needs to stop a 10kg salmon (fish) swimming at 9m/s in a distance of 4.5m ? (Assume deceleration of salmon due to fishing line is constant)
A
70N
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B
80N
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C
90N
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D
100N
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Solution
The correct option is C90N Given, Initial velocity of fish, u=9m/s
Final velocity of fish, v=0m/s (to stop salmon)
Distance covered by fish before stopping, s=4.5m
Using v2−u2=2as 0−92=2(4.5)×a
Deceleration, ⇒→a=9m/s2
Using Newton's second law, |→F|=m|→a| F=10×9=90N