What sum will amount to $R s 261.25$ in $1 y e a r 6 m o n t h s$ at $3 % p e r m o n t h$ SI ?

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Solution

$A = R s 261.25 T = 1 y e a r 6 m o n t h s = 1 \frac{6}{12} y = 1 \frac{1}{2} y = \frac{3}{2} y R = 3 % p e r m o n t h = 3 \times 12 % p . a . = 36 % p . a . L e t P b e t h e p r i n c i p a l . S I = \frac{P \times R \times T}{100} = \frac{P \times 36 \times 3}{100 \times 2} = \frac{54 P}{100} A = P + S I = P + \frac{54 P}{100} = \frac{154 P}{100} A c c o r d i n g t o q u e s t i o n, \frac{154 P}{100} = 261.25 P = \frac{261.25 \times 100}{154} = R s 169.64$

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