What type of isomerism is exhibited by? CH3CH2CH2−O||C−O−CH2CH3 CH3CH2−O||C−O−CH2CH2CH3
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Solution
CH3−CH2−CH2−O||C−O−CH2CH3 and CH3−CH2−O||C−OCH2CH2CH3 exhibit metamerism as they have same molecular formula C6H12O2 & differ in number of C− atoms on either side of functional group −O||C−O.