What type of orbital hybridisation is considered on P in $P C l_{5}$ ?

s p^{3} d

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d s p^{3}

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s p^{3} d^{2}

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d^{2} s p^{3}

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Solution

The correct option is A $s p^{3} d$
In $P C l_{5}$ , number of hybrid orbitals,
$h = \frac{1}{2} [V + X + A - C]$
[where, $V = number of valence electrons X = number of monovalent atoms A and C=charge of cation or anion]$
$H = \frac{1}{2} [5 + 5 + 0 = 0]$
Thus, the hybridisation is $s p^{3} d$ .

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Similar questions

What is the hybridization of P in $P C l_{5} (s)$ ?

s p^{3} d^{2}

d^{2} s p^{3}

The correct order of hybridisation of the central atom in the following species $N H_{3}$ , ${[P t C l_{4}]}^{2 -}$ , $P C l_{5}$ and $B C l_{3}$

P C l_{5}

s p^{3} d

P C l_{5}

\begin{matrix} Column - I & Column - II (Complex ion) & (CFSE and hybridisation) a . {[C r (N H_{3})_{6}]}_{3}^{3 +} & (P) 0.0 Δ_{0}, s p^{3} d^{2} - hybridisation b . {[C u (N H_{3})_{6}]}_{3}^{2 +} & (Q) - 0.6 Δ_{0}, s p^{3} d^{2} - hybridisation c . {[F e (H_{2} O)_{6}]}_{2}^{3 +} & (R) - 1.2 Δ_{0}, d^{2} s p^{3} - hybridisation d . {[I r F_{6}]}_{6}^{3 -} & (S) Diamagnetic (T) Paramagnetic \end{matrix}

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