What value of x makes the equation 4 a b c-1-3 a b c-x-2-3 a b c-0 true -A- -6 a b cB- -5 a b cC- -8 a b cD- -7 a b c

The correct option is B 5abc 4abc+1/3abc+ x+2/3abc=0 x=0 4abc 1/3abc 2/3abc x=0 4abc (1/3+2/3)abc x= 4abc (1)abc x= 5abc ...

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Subtraction of Polynomials

What value of...

Question

What value of $x$ makes the equation $4 a b c + \frac{1}{3} a b c + x$ + $\frac{2}{3} a b c$ =0 true ?

-6abc

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-5abc

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-8abc

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-7abc

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Similar questions

4 a b c + \frac{1}{3} a b c +

\frac{2}{3} a b c

$4 a b c + \frac{1}{3} a b c +$ ___ $+$ $\frac{2}{3} a b c$ = 0

a^{3} + b^{3} + c^{3} - 3 a b c = 0

(a^{2} - b c) x^{2} + 2 (b^{2} - a c) x + c^{2} - a b = 0

3 a b c, \frac{5}{2} a^{2} b c, \frac{- 3}{5} a b^{2} c, \frac{4}{7} a b c, 11 a b c^{2}, \frac{13}{3} a^{2} b c, \frac{4}{7} {a b}^{2} c, \frac{17}{3} {a b c}^{2}, \frac{29}{2} a b c

(c^{2} - a b) x^{2} - 2 (a^{2} - b c) x + (b^{2} - a c) = 0

a = 0

a^{3} + b^{3} + c^{3} + = 3 a b c

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