What value should come in place of the question mark (?) in the following equation?
$48 \sqrt{?} + 32 \sqrt{?} = 320$

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Solution

The correct option is A 16
Let $? = x$
Therefore,
$48 \sqrt{x} + 32 \sqrt{x} = 320$
$\Rightarrow 80 \sqrt{x} = 320$
$\Rightarrow \sqrt{x} = \frac{320}{80}$
$\Rightarrow \sqrt{x} = 4$
$\Rightarrow x = 16$ ...Squaring on both sides

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