What volume in litres of a solution of hydrochloric acid containing 73 g of acid per litre would be sufficient for the exact neutralization of sodium hydroxide obtained by allowing 0.46 g of metallic sodium to act upon water?
A
5
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B
15
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C
10
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D
20
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Solution
The correct option is C10
The balanced reaction is as follows:
2Na + 2H2O→2NaOH + H2 Moles of metallic sodium =0.4623=0.02 Moles of HCl= Moles of NaOH Molarity × Volume = Number of moles 7336.5×1×V=0.02⟹V=10 Hence, volume of the solution required would be 10 L.