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Question

What volume of 0.05 M K2Cr2O7 in acidic medium is needed for complete oxidation of 200 mL of 0.6 M FeC2O4 solution?

A
1.4 L
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B
1.2 L
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C
120 mL
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D
800 mL
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Solution

The correct option is A 1.2 L
Cr2O270.05 M+FeC2O40.6 M/200 mLH Cr2O27+14H+6e2Cr3++7H2O
Fe2+Fe3++e;
C2O242CO2+2e
FeC2O4Fe3++2CO2+3e
m. Eq.of K2Cr2O7m.Eq. of FeC2O4
(0.05×6)×V=(0.6×3)×200
V=1200 mL=1.2 L

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