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Standard X

Chemistry

Volume of Gases and Number of Moles

What volume o...

Question

What volume of 0.1N $H N O_{3}$ solution can be prepared from 6.3 g of $H N O_{3}$ ?

1 litre

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2 litres

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0.5 litre

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5 litres

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Solution

The correct option is A 1 litre
$Molecular wt of {H N O}_{3} = 63$

$Normality = \frac{mole of solute}{volume of solvent in L}$

$0 \cdot 1 = \frac{6 \cdot 3}{63 \times Volume of solvent (L)}$

$volume of solvent =1 L$

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Similar questions

Q. The volume of

0.1 N H N O_{3}

solution that can be prepared from

6.3 g m

H N O_{3}

is:

1

litre of solution contains

18.9

g of

H N O_{3}

and

1

litre of another solution contains

3.2

g of NaOH. In what volume ratio must these solutions be mixed to obtain a solution having a neutral reaction?

(1 : 3.75)

Q. Determine the volume of dilute nitric acid (

d = 1.11

m L^{- 1}

19 %

w/w

H N O_{3}

) that can be prepared by diluting with water

50

mL of conc.

H N O_{3}

(

d = 1.42

m L^{- 1}

69.8 %

w/w).

Q. One litre of a solution contains

18.9

g of

H N O_{3}

and one litre of another solution contains

3.2

g of

N a O H

. In what volume ratio must these solutions be mixed to obtain a neutral solution?

150 g

of a solution

(d = 1.2 g / m l)

contains

63 g

H N O_{3}

. What volume of this

H N O_{3}

(in mL) solution will be required to react with a

N a O H

solution, containing

24 g

N a O H

?
Reaction:

H N O_{3} + N a O H \to N a N O_{3} + H_{2} O

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What volume of 0.1N HNO3 solution can be prepared from 6.3 g of HNO3?

The correct option is A 1 litre Molecular wt of HNO3=63 Normality = mole of solute volume of solvent in L 0⋅1=6⋅363× Volume of solvent (L) volume of solvent =1 L

What volume of 0.1N $H N O_{3}$ solution can be prepared from 6.3 g of $H N O_{3}$ ?

The correct option is A 1 litre
$Molecular wt of {H N O}_{3} = 63$

$Normality = \frac{mole of solute}{volume of solvent in L}$

$0 \cdot 1 = \frac{6 \cdot 3}{63 \times Volume of solvent (L)}$

$volume of solvent =1 L$