Question

What volume of $0.4M$ $Fe{Cl}_3\cdot 6H_{2}O$ will contain $600mg$ of ${Fe}^{3+}$?

• A. $49.85ml$
• B. $26.785ml$
• C. $147.55ml$
• D. $87.65ml$

Answer 1

Answer: (B)

$26.785ml$

Millimoles of ${Fe}^{3+}=\frac{600}{56}$

Millimoles of ${Fe}^{3+}=$ Millimoles of $Fe{Cl}_3.6H_{2}O$

$\frac{600}{56}=0.4\times V$

$\therefore 10.71=0.4V$

$V=26.785ml$

Hence, option B is correct.