Question

What volume of $1$M $NaOH$ (in mL) will be required to react completely with $100$g of oleum which is $109\%$ labelled?

• A. $250.5$ mL
• B. $2224.5$ mL
• C. $750.5$ mL
• D. $1800.5$ mL

Answer 1

The correct option is B $2224.5$ mL

Let us consider the problem:

For,

$109\%$ oleum means 9g of $H_{2}O$is required to convert all $S{O}_3$present in $100$gm of it to $H_{2}S{O}_4$.

Therefore,

$S{O}_3+H_{2}0=H_{2}S{O}_4$

Hence that is $\frac{100\times 88.98}{40}=2224.5$ml.