The correct option is B 125mL
Let V mL of a 0.8 M solution contains 100 millimoles of the solute
The number of moles of solute are VmL1000mL/L×0.8mol/L
But this is equal to 100 millimoles or 0.1 mole.
Hence, VmL1000mL/L×0.8mol/L=0.1
V=0.1×10000.8=125mL
Thus, 125 mL of a 0.8 M solution contains 100 millimoles of the solute.