Question

What volume of a $3M$ solution of $NaOH$ is required to titrate $0.05L$ of a $4M$ solution of $HCl$ to the equivalence point?

• A. $\frac{1}{10}$ L
  
• B. $\frac{1}{15}$ L
• C. $\frac{1}{20}$ L
• D. None of the above
  

Answer 1

The correct option is B $\frac{1}{15}$ L

$M_1{V}_1=M_2{V}_2$ at point of equivalence, because the n-factor for both acid and base are same.
$3\times V_1=4\times 0.05$
$V_1=\left(V_{NaOH}\right)=\frac{1}{15}L$