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Question

What volume of air at 1 atm and 273 K that has 21% of oxygen by volume is required to completely burn sulphur (S8) present in 200 g of a sample, which contains 20% inert material that does not burn? Sulphur burns according to the reaction:
18S8(s)+O2(g)SO2(g)

A
23.52 litre
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B
320.0 litre
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C
112.0 litre
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D
533.3 litre
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Solution

The correct option is D 533.3 litre
1 mol of oxygen is required to burn 1 mol of S.
1 mol of oxygen is required to burn 32g of S
So, to burn 160 g of sulphur 16032, 5 mol of O2 is required
At STP, 5×22.4L of oxygen is consumed in the reaction.
Since 21% of oxygen is consumed in the reaction,
The total volume of air involed in the reaction is =10021×5×22.4L=533.3 L

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