What volume of air (containing 20 % $O_{2}$ by volume) will be required to burn completely $10 c m^{3}$ each of methane and acetylene.
$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O 2 C_{2} H_{2} + 5 O_{2} \to 4 C O_{2} + 2 H_{2} O$

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Solution

Burning of methane:

$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$

According to the reaction,
For complete burning 1 volume of methane, 2 volumes of Oxygen is required.
Hence, for burning 10 of methane, 20 of oxygen is required.
Since, air contains 20% of oxygen. So 100 of air will be required containing 20 of oxygen.

Burning of acetylene:

$2 C_{2} H_{2} + 5 O_{2} \to 4 C O_{2} + 2 H_{2} O$

According to the reaction,
For complete burning 1 volume of acetylene, $\frac{5}{2}$ volumes of Oxygen is required.
Hence, for burning 10 of acetylene, $\frac{5}{2} \times 10 = 25 c m^{3}$ of oxygen is required.
Since air contains 20% oxygen.
So, 20 oxygen is present in 100
Therefore, 25 oxygen will be present in $\frac{100}{20} \times 25 = 125 c m^{3}$
Hence, 125 of air will be required containing 25 of oxygen.

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Q. Acetylene

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What volume of air (containing 20 % O2 by volume) will be required to burn completely 10cm3 each of methane and acetylene. CH4+2O2→CO2+2H2O2C2H2+5O2→4CO2+2H2O

What volume of air (containing 20 % $O_{2}$ by volume) will be required to burn completely $10 c m^{3}$ each of methane and acetylene.
$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O 2 C_{2} H_{2} + 5 O_{2} \to 4 C O_{2} + 2 H_{2} O$