Question

What volume of CH₄ at NTP contains same number of molecules as atoms in 16g of S₈ ?

Answer 1

Step 1:

Molecules of $C{H}_4$ = $\frac{VolumeofC{H}_4}{22.4}\times N_A$
Molecules of $S_8=\frac{Mass}{molecularmass}\times N_A$

Step 2:
Since,
​​​​​​Molecules of $C{H}_4$ = Molecules of $S_8$

$\frac{VolumeofC{H}_4}{22.4}\times N_A=\frac{Mass}{molecularmass}\times N_A$

Volume of $C{H}_4=$ $\frac{16}{256}\times 22.4=1.4L$

​​​​Hence, the volume of $C{H}_{4}is1.4L$ .
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