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Introduction to Oxidation and Reduction

What volume o...

Question

What volume of $C O_{2}$ at STP (atm) will be produced when $1 g$ of $C a C O_{3}$ reacts with an excess of dilute $H C l$ (in ml).

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Solution

$C a C O_{3} + 2 H C l \to C a C l_{2} + C O_{2} + H_{2} O$

1 mol of $C a C O_{3}$ produces 1 mol of $C O_{2} = 22.4 L$ of $C O_{2}$ gas, i.e.
$100 g$ of $C a C O_{3}$ produces $22400 mL$ of $C O_{2}$ gas.
$1 g$ of $C a C O_{3}$ will produce = $\frac{22400}{100} mL$ of $C O_{2}$ gas.

Volume of $C O_{2}$ gas produced = $224 mL$

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