What volume of CO2 will be liberated at STP (1 atm, 273 K), If 7.2 gm of carbon is burnt in excess of oxygen?
A
13.4 L
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B
2.24 L
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C
1.12 L
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D
11.2 L
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Solution
The correct option is A13.4 L C + O2→CO2
We have given 7.2 gm of C and Volume of CO2 at STP is asked.
Moles of Carbon = 7.212=0.6mol
As per stoichiometry,
1 mol of C produces 1 mol of CO2.
Hence, 0.6 mol of C produces 0.6 mol of CO2