10 gram of hydrogen is liberated by the electrolysis of NaOH solution at the cost of Rs.20. The cost of current to liberate 10gram of oxygen under similar conditions is in :

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What volume of H2 is liberated under similar conditions which released 2.24dm3O2 by electrolysis of water?

The correct option is B 4.48dm3Since volume of H2 is twice (when electrolysis of H2O is carried out) then that of O2.H2O→H2+12O2So,volume=(2×2.24)=4.48dm3

What volume of $H_{2}$ is liberated under similar conditions which released $2.24 d m^{3} O_{2}$ by electrolysis of water?

The correct option is B $4.48 d m^{3}$
Since volume of $H_{2}$ is twice (when electrolysis of $H_{2} O$ is carried out) then that of $O_{2}$ .
$H_{2} O \to$ $H_{2} + \frac{1}{2} O_{2}$
$S o, v o l u m e = (2 \times 2.24)$ $= 4.48 d m^{3}$