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Question

What volume of hydrogen gas, at 273 K and 1 atm pressure will be consumed in obtaining 21.6 g of elemental boron (atomic mass = 10.8) from the reduction of boron trichloride by hydrogen?

A
89.6 L
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B
67.2 L
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C
44.8 L
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D
22.4 L
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Solution

The correct option is B 67.2 L
The reaction would be 2BCl3+3H22B+6HCl

In the reaction to obtain 2 moles of elemental boron at S.T.P requires 3 moles of H2 gas.

The moles of boron in 21.6 g=21.610.8=2 moles

These 2 moles of B need 3 moles of H2 at STP.

The volume of 1 mole of gas at STP=22.4 L

Therefore, the volume of 3 moles=22.4×3=67.2 L

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