Question

What volume of hydrogen will be liberated at NTP by the reaction of Zn on 50 ml. dilute $H_{2}S{O}_4$ of specific gravity 1.3 and having purity 40% ?

• A. 3.5 litre
• B. 8.25 litre
• C. 6.74 litre
• D. 5.94 litre

Answer 1

The correct option is D 5.94 litre

Mass of $H_{2}S{O}_4=\frac{50\times 1.3\times 40}{100}=26g$

A balanced chemical equation will be as:
$Zn+H_{2}S{O}_4\to ZnS{O}_4+H_2$
Volume of $H_2$ librated at normal temperature and pressure is =$\frac{22.4}{98}\times 26=5.94litre$