What volume of $N O_{2}$ gas at $27^{o} C$ and $1.0$ atm pressure would be produced?

6.97

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5.97

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4.97

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3.97

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Solution

The correct option is A $6.97$ L
$N O_{2}$ gas is produced only with Cu and $H N O_{3}$ .
Mol of $N O_{2}$ with $C u$ and $H N O_{3} = (9.0 g C u) (\frac{1 m o l C u}{63.5 g}) (\frac{2 m o l N O_{2}}{1 m o l C u})$
$= \frac{9 \times 1 \times 2}{63.5 \times 1} = 0.283 {mol NO}_{2}$
$V = \frac{n R T}{P}$
$= \frac{(0.283 mol) (0.082 {L atm mol}^{- 1} K^{- 1}) \times 300 K}{1.00 a t m}$
$= 6.97 L$
Hence, the correct option is $A$

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