What volume of oxygen at STP is required to effect complete combustion of $200 c m^{3}$ of ethylene?
$C_{2} H_{2} + 5 O_{2} \to 4 C O_{2} + 2 H_{2} O$

40 c m^{3}

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500 c m^{3}

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400 c m^{3}

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200 c m^{3}

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Solution

The correct option is B $500 c m^{3}$
$2 C_{2} H_{2} + 5 O_{2} \to 4 C O_{2} + 2 H_{2} O$
STP, 1Mole $= 22.414 d m^{3} = 22414 c m^{3}$
Therefore, $200 c m^{3} = \frac{200}{22414} m o l e s = 8.92 \times 10^{- 3} m o l e s$
Moles of ethylene $= 8.92 \times 10^{- 3}$ moles
Moles of oxygen required $= \frac{5}{2} \times 8.92 \times 10^{- 3} = 0.022$ moles
Volume of oxygen required $= 0.022 \times 22414$
$= 500 c m^{3}$

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What volume of oxygen at STP is required to effect complete combustion of 200cm3 of ethylene?C2H2+5O2→4CO2+2H2O

The correct option is B 500cm32C2H2+5O2→4CO2+2H2O STP, 1Mole=22.414dm3=22414cm3Therefore,200cm3=20022414moles=8.92×10−3moles Moles of ethylene =8.92×10−3 molesMoles of oxygen required =52×8.92×10−3=0.022molesVolume of oxygen required =0.022×22414=500cm3

What volume of oxygen at STP is required to effect complete combustion of $200 c m^{3}$ of ethylene?
$C_{2} H_{2} + 5 O_{2} \to 4 C O_{2} + 2 H_{2} O$