What volume of oxygen gas at STP is necessary for complete combustion of 20.0 litre of propane $(C H_{3} C H_{2} C H_{3})$ , measured at $27^{o} C$ and 760 mm of $H g$ ?

95 lit

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91 lit

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80 lit

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70 lit

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Solution

The correct option is A 91 lit
$C H_{3} C H_{2} C H_{3} + 5 O_{2} \to 3 C O_{2} + 4 H_{2} O$

Moles of propane $= \frac{P V}{R T} = \frac{1 \times 20}{0.0821 \times 300} = 0.812 m o l e s$

Volume of $O_{2}$ required at STP $= \frac{n R T}{P} = 5 \times \frac{0.812 \times 0.0821 \times 273}{1} = 91 l i t r e s$

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