Question

What volume of oxygen gas $\left(O_2\right)$ measured at $0^0$C and $1$ atm, is needed to burn completely $1$L, of propane gas $\left(C_3{H}_8\right)$ measured under the same conditions?

Answer 1

$C_3{H}_8+5O_2⟶3C{O}_2+4H_{2}O$

$1$ mole of $C_3{H}_8$ requires $5$ mole of $O_2$

$\therefore 1$ mole $=22.4d{m}^3$

$1\times 22.4d{m}^3$ propane needs $5\times 22.4d{m}^3$

$\therefore 5L$ of oxygen is required to burn $1L$ of propane completely.