Question

# What volume of oxygen would be required for complete combustion of 100 litres of ethane according to the following equation? 2C2H6 + 7O2 $\stackrel{}{\to }$ 4CO2 + 6H2O

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Solution

## Number of moles of ethane in 100 L = $\frac{\mathrm{Volume}\mathrm{of}\mathrm{ethane}}{\mathrm{Molar}\mathrm{volume}\mathrm{of}\mathrm{ethane}}=\frac{100}{22.4}=4.46\mathrm{L}$ According to the balanced chemical equation, two moles of ethane require seven moles of oxygen for complete combustion. Moles of oxygen required by 4.46 moles of ethane = $\frac{7}{2}×\frac{100}{22.4}$ Volume of oxygen required = Number of moles $×$ Molar volume = $\left(\frac{7}{2}×\frac{100}{22.4}\right)×22.4=350\mathrm{L}$ (22.4)

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